Intermediate Algebra (11th edition)

(Marvins-Underground-K-12) #1

FIGURE 2shows the graph of the cube root function.Since any real number (pos-


itive, negative, or 0) can be used for xin the cube root function, can be positive,


negative, or 0. Thus, both the domain and the range of the cube root function are


1 - q, q 2.


23 x


430 CHAPTER 8 Roots, Radicals, and Root Functions


2
1

x


x


  • 8

  • 1
    0
    1
    8

    • 2

    • 1
      0
      1
      2
      18




y


  • 2

  • 8


f (x)^3 x


f (x)^3 x


FIGURE 2

Cube root function

Domain:
Range: 1 - q, q 2

1 - q, q 2

ƒ 1 x 2  23 x

Graphing Functions Defined with Radicals

Graph each function by creating a table of values. Give the domain and range.


(a)


A table of values is given with the graph in FIGURE 3. The x-values were chosen in


such a way that the function values are all integers. For the radicand to be nonnega-


tive, we must have


or


Therefore, the domain of this function is Function values are positive or 0, so


the range is 3 0, q 2.


3 3, q 2.


x- 3 Ú0, xÚ 3.


ƒ 1 x 2 = 2 x- 3


EXAMPLE 3


x

y

0

1

2
34 7

f(x) = √x – 3

FIGURE 3

x

y

f(x) = √^3 x + 2

–1 1

1
2

4

–8 8

FIGURE 4

x
3
4
7 27 - 3 = 2

24 - 3 = 1

23 - 3 = 0

ƒ 1 x 2 = 2 x- 3

x

0
1
8 238 + 2 = 4

231 + 2 = 3

230 + 2 = 2


  • 1 23 - 1 + 2 = 1

  • 8 23 - 8 + 2 = 0


ƒ 1 x 2 = 23 x+ 2

(b)


See FIGURE 4. Both the domain and range are 1 - q, q 2.


ƒ 1 x 2 = 23 x+ 2


NOW TRY

NOW TRY
EXERCISE 3
Graph each function. Give the
domain and range.


(a)


(b)ƒ 1 x 2 = 23 x- 1


ƒ 1 x 2 = 2 x+ 1

NOW TRY ANSWERS



  1. (a)


domain: ;
range:
(b)

domain: ;
range: 1 - q, q 2

1 - q, q 2

0

y

x
–1 1
–2

f(x) = ^3 x – 1

3 0, q 2

3 - 1, q 2

2
0

y
x
–1 3

f(x) = x + 1
Free download pdf