Intermediate Algebra (11th edition)

(Marvins-Underground-K-12) #1

436 CHAPTER 8 Roots, Radicals, and Root Functions


Evaluating Exponentials of the Form

Evaluate each exponential.


(a) (b)


(c)


(d) is not a real number, because the radicand, is


negative and the index is even.


(e) (f ) a


1


8


b


1/3

=


B


3


1


8


=


1


2


1 - 322 1/5= 25 - 32 =- 2


1 - 2562 1/4= 24 - 256 - 256,


- 256 1/4 = - 24256 = - 4


64 1/3= 2364 = 4 100 1/2 = 2100 = 10


EXAMPLE 1 a1/n
NOW TRY
EXERCISE 1
Evaluate each exponential.


(a) (b)


(c) (d)


(e) (f ) a


1


16


b

1/4
1 - 1252 1/3

- 625 1/4 1 - 6252 1/4


81 1/2 125 1/3


The denominator
is the index.

The denominator is
the index.
2 means.^22

NOW TRY

CAUTION Notice the difference between Examples 1(c) and (d).The radical in


part (c) is the negative fourth root of a positive number,while the radical in part (d)


is the principal fourth root of a negative number, which is not a real number.


OBJECTIVE 2 Define and use expressions of the form We know that


We can define a number like , where the numerator of the exponent is


not 1. For past rules of exponents to be valid,


Since


Generalizing from this example, we define am/nas follows.


8 2/3= A 238 B


2

= 22 =4.


8 1/3= 238 ,


8 2/3= 81 1/3^22 = 18 1/3 22.


8 1/3= 238. 8 2/3


am/n.


If mand nare positive integers with in lowest terms, then


provided that is a real number. If is not a real number, then is not a


real number.


a1/n a1/n am/n


am/n 1 a1/n 2 m,


m/n


am/n

Evaluating Exponentials of the Form

Evaluate each exponential.


(a) (b)


(c)


Because the base here is 4, the negative sign is notaffected by the exponent.


- 4 5/2 = - 14 5/2 2 = - 14 1/2 25 = - 1225 = - 32


36 3/2= 136 1/2 23 = 63 = 216 125 2/3= 1125 1/3 22 = 52 = 25


EXAMPLE 2 am>n

Be careful.
The base is 4.

Think:
125 1/ 3= 23125 = 5

Think:
36 1/2= 236 = 6

NOW TRY ANSWERS



  1. (a) 9 (b) 5 (c)
    (d)It is not a real number.
    (e) - 5 (f )^12

    • 5



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