To solve use the quadratic formula with and
Substitute.
Solve for t.
The solutions are and NOW TRY
OBJECTIVE 2 Solve applied problems using the
Pythagorean theorem.The Pythagorean theorem, repre-
sented by the equation
is illustrated in FIGURE 2and was introduced in Section 8.3.
It is used to solve applications involving right triangles.
Using the Pythagorean Theorem
Two cars left an intersection at the same time, one heading due north, the other due
west. Some time later, they were exactly 100 mi apart. The car headed north had gone
20 mi farther than the car headed west. How far had each car traveled?
Step 1 Readthe problem carefully.
Step 2 Assign a variable.
Let the distance traveled by the car
headed west.
Then the distance traveled by the car
headed north.
See FIGURE 3. The cars are 100 mi apart, so the
hypotenuse of the right triangle equals 100.
Step 3 Write an equation.Use the Pythagorean theorem.
Step 4 Solve. Square the binomial.
Standard form
Divide by 2.
Factor.
or Zero-factor property
or Solve for x.
Step 5 State the answer.Since distance cannot be negative, discard the negative
solution. The required distances are 60 mi and mi.
Step 6 Check.Since 602 + 802 = 1002 ,the answer is correct. NOW TRY
60 + 20 = 80
x=- 80 x= 60
x+ 80 = 0 x - 60 = 0
1 x+ 8021 x- 602 = 0
x^2 + 20 x- 4800 = 0
2 x^2 + 40 x- 9600 = 0
x^2 + x^2 + 40 x+ 400 = 10,000
x^2 + 1 x+ 2022 = 1002
a^2 +b^2 = c^2
x+ 20 =
x=
EXAMPLE 3
a^2 b^2 c^2 ,
t=
- k- 2 k^2 + 8 s
4
t=.
- k+ 2 k^2 + 8 s
4
t=
- k 2 k^2 + 8 s
4
t=
- k 2 k^2 - 41221 - s 2
2122
c=-s.
2 t^2 +kt- s=0, a=2, b=k,
524 CHAPTER 9 Quadratic Equations, Inequalities, and Functions
North
Intersection
West
100
x
x + 20
90 °
FIGURE 3
1 x+y 22 =x^2 + 2 xy+y^2
NOW TRY
EXERCISE 3
Matt Porter is building a new
barn, with length 10 ft more
than width. While determin-
ing the footprint of the barn,
he measured the diagonal as
50 ft. What will be the dimen-
sions of the barn?
NOW TRY
EXERCISE 2
Solve for r.
r^2 + 9 r=-c
NOW TRY ANSWERS
- 30 ft by 40 ft
r=
- 9 281 - 4 c
2
90 °
a^2 + b^2 = c^2
c
Hypotenuse
Pythagorean theorem
Leg b
Leg a
FIGURE 2