- (a)Use the graph to estimate spending on physician and clinical services in 2005 to the
nearest $10 billion.
(b)Use the model to approximate spending to the nearest $10 billion. How does this
result compare to your estimate in part (a)?
60.Based on the model, in what year did spending on physician and clinical services first
exceed $350 billion? (Round down for the year.) How does this result compare to the
amount of spending shown in the graph?
61.Based on the model, in what year did spending on physician and clinical services first
exceed $400 billion? (Round down for the year.) How does this result compare to the
amount of spending shown in the graph?
62.If these data were modeled by a linearfunction defined by would the
value of abe positive or negative? Explain.
Find each function value. See Section 3.6.
65.Graph ƒ 1 x 2 = 2 x^2 .Give the domain and range. See Section 5.3.
ƒ 1 x 2 =x^2 + 4 x-3. Find ƒ 122. ƒ 1 x 2 = 21 x- 322 +5. Find ƒ 132.
PREVIEW EXERCISES
ƒ 1 x 2 =ax+b,
SECTION 9.5 Graphs of Quadratic Functions 531
Spending on Physician and Clinical Services
Source: U.S. Centers for Medicare and Medicaid
Services.
Year
Billions of Dollars
500
400
300
200
100
0
2000 2001 2002 2003 2005 2004 20062007
OBJECTIVES
Graphs of Quadratic Functions
9.5
1 Graph a quadratic
function.
2 Graph parabolas
with horizontal and
vertical shifts.
3 Use the coefficient
of x^2 to predict the
shape and direction
in which a parabola
opens.
4 Find a quadratic
function to model
data.
OBJECTIVE 1 Graph a quadratic function. FIGURE 5gives a graph of the sim-
plest quadratic function,defined by This graph is called a parabola.(See
Section 5.3.) The point the lowest point
on the curve, is the vertexof this parabola. The
vertical line through the vertex is the axisof the
parabola, here A parabola is symmetric
about its axis— if the graph were folded along
the axis, the two portions of the curve would
coincide.
As FIGURE 5 suggests, xcan be any real
number, so the domain of the function defined
by is Since yis always non-
negative, the range is 3 0, q 2.
y= x^21 - q, q 2.
x= 0.
1 0, 0 2 ,
y= x^2.
–2^02
2
4
Vertex
Axis
x
y
y = x^2
FIGURE 5
xy
4
1
00
11
24
- 1
- 2