Intermediate Algebra (11th edition)

(Marvins-Underground-K-12) #1

OBJECTIVE 5 Use logarithmic functions in applications involving growth


or decay.


Solving an Application of a Logarithmic Function

The function defined by


approximates the barometric pressure in inches


of mercury at a distance of xmiles from the eye


of a typical hurricane. (Source:Miller, A. and


R. Anthes, Meteorology,Fifth Edition, Charles


E. Merrill Publishing Company.) Approximate


the pressure 9 mi from the eye of the hurricane.


Let and find


Let

Add inside parentheses.

Add.

The pressure 9 mi from the eye of the hurricane is 28.105 in. NOW TRY


ƒ 192 =28.105


ƒ 192 = 27 + 1.105 112 log 10 10 = 1


ƒ 192 = 27 + 1.105 log 10 10


ƒ 192 = 27 + 1.105 log 10 19 + 12 x=9.


x= 9, ƒ 192.


ƒ 1 x 2 = 27 +1.105 log 10 1 x+ 12


EXAMPLE 6


592 CHAPTER 10 Inverse, Exponential, and Logarithmic Functions


Complete solution available
on the Video Resources on DVD


10.3 EXERCISES


1.Concept Check Match the logarithmic
equation in Column I with the corre-
sponding exponential equation from
Column II. See Example 1.
III
(a) A.

(b) B.

(c) C.

(d) D.

(e) E.

(f ) F.

2.Concept Check Match the logarithm
in Column I with its value in Column II.
(Example: because 2 is the
exponent to which 3 must be raised in
order to obtain 9.)
III
(a) A.
(b) B.

(c) C. 2

(d) D. 0

(e) E.

(f ) log 13 1 F. 4

1


2


log 525

log 10 0.01

log 3 a

1


3


b

log 3 81 - 1

log 4 16 - 2

log 3 9 = 2

log 4 4 = 1 103 = 1000

log 8238 = 50 = 1

1


3


log 10 1000 = 3 2 1/2= 22

log 222 = 41 = 4

1


2


a

1


3


b


  • 1
    log 5 1 = 0 = 3


log1/3 3 =- 1 8 1/3= 238

Write in logarithmic form. See Example 1.

















7. 8. 9. 10.


11. 12. 16 - 3/4= 13. 50 = 1 14. 70 = 1


1


8


8 - 2/3=


1


4


10 -^3 =0.001 36 1/2= 6 24625 = 5 23343 = 7


a

1


6


b


  • 3
    a = 216


1


2


b


  • 3
    45 = 1024 36 = 729 = 8


NOW TRY
EXERCISE 6
Suppose the gross national
product (GNP) of a small
country (in millions of dol-
lars) is approximated by


where tis time in years since



  1. Approximate to the
    nearest tenth the GNP for
    each value of t.


(a)t= 1 (b)t= 10


G 1 t 2 =15.0+2.00 log 10 t,

NOW TRY ANSWERS



  1. (a)$15.0 million
    (b)$17.0 million

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