Geometry with Trigonometry

(Marvins-Underground-K-12) #1

Sec. 10.5 Sensed-area 157


Note that

δF(Z 1 ,Z 2 ,Z 3 )=δF(Z 2 ,Z 3 ,Z 1 )=δF(Z 3 ,Z 1 ,Z 2 )
=−δF(Z 1 ,Z 3 ,Z 2 )=−δF(Z 2 ,Z 1 ,Z 3 )=−δF(Z 3 ,Z 2 ,Z 1 ),

so that its value is unchanged ifZ 1 ,Z 2 ,Z 3 are permuted cyclically, and its value is
multiplied by−1 if the order of these is changed.
We note also that 10.4.1(ii) can be restated as that the sensed-angleFZ 1 Z 0 Z 2 is
wedge or reflex according as



z 2 −z 0
z 1 −z 0

=ℑ


Z 0 Z 2 F


Z 0 Z (^1) F
is positive or negative, and this occurs according asδF(Z 0 ,Z 1 ,Z 2 )is positive or neg-
ative.


10.5.3Abasicfeatureofsensed-area.....................


A basic feature of sensed-area is given by the following. Let the pointsZ 3 ≡(x 3 ,y 3 ),
Z 4 ≡(x 4 ,y 4 ),Z 5 ≡(x 5 ,y 5 )be such that


x 3 =( 1 −s)x 4 +sx 5 ,y 3 =( 1 −s)y 4 +sy 5 ,

for somes∈R. Then for allZ 1 ,Z 2 ,


δF(Z 1 ,Z 2 ,Z 3 )=( 1 −s)δF(Z 1 ,Z 2 ,Z 4 )+sδF(Z 1 ,Z 2 ,Z 5 ).

For


δF(Z 1 ,Z 2 ,Z 3 )=

1


2


det



x 1 y 1 1
x 2 y 2 1
( 1 −s)x 4 +sx 5 ( 1 −s)y 4 +sy 5 ( 1 −s)+s



=


1


2


det



x 1 y 1 1
x 2 y 2 1
( 1 −s)x 4 ( 1 −s)y 4 1 −s


⎠+^1


2


det



x 1 y 1 1
x 2 y 2 1
sx 5 sy 5 s



=


1


2


( 1 −s)det



x 1 y 1 1
x 2 y 2 1
x 4 y 4 1


⎠+^1


2


sdet



x 1 y 1 1
x 2 y 2 1
x 5 y 5 1



=( 1 −s)δF(Z 1 ,Z 2 ,Z 4 )+sδF(Z 1 ,Z 2 ,Z 5 ).

10.5.4 An identity for sensed-area .....................


An identity that we have for sensed-area is that for any pointsZ 1 ,Z 2 ,Z 3 ,Z 4 ,


δF(Z 4 ,Z 2 ,Z 3 )+δF(Z 4 ,Z 3 ,Z 1 )+δF(Z 4 ,Z 1 ,Z 2 )=δF(Z 1 ,Z 2 ,Z 3 ).
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