Geometry with Trigonometry

(Marvins-Underground-K-12) #1

164 Complex coordinates; sensed angles; angles between lines Ch. 10


10.9 Someresultsoncircles ........................


10.9.1 A necessary condition to lie on a circle ...............


In this section we provide some results on circles which are conveniently proved
using complex coordinates.
Let Z 1 ,Z 2 be fixed distinct
points, and Z a variable point,
all on the circle C(Z 0 ;k).
Let F′ = tO,Z 0 (F) and
α=∠F′I 0 Z 0 Z 1 ,β=∠F′I 0 Z 0 Z 2
andγ=^12 (β−α). As Z varies
on the circle, in one of the open
half-planes with edge Z 1 Z 2
the sensed angle FZ 1 ZZ 2 is
equal in measure to γ, while
in the other open half-plane
with edge Z 1 Z 2 it is equal in


measure toγ+ (^180) F′. Note that
2 γ=FZ 1 Z 0 Z 2.


O I


J H^1


H 2


H 4 H 3








Z 0 I 0


J 0


Z 1


Z 2


Z


α

β

Figure 10.8.

Proof.Nowz 1 −z 0 =kcisα,z 2 −z 0 =kcisβand ifθ=FI 0 Z 0 Z,thenz−z 0 =
kcisθ.We writeφ=FZ 1 ZZ 2 so that


z 2 −z
z 1 −z

=lcisφ,wherel=

|Z,Z 2 |


|Z,Z 1 |


.


Then


lcisφ=

cisβ−cisθ
cisα−cisθ

,


while on taking complex conjugates here


lcis(−φ)=

cis(−β)−cis(−θ)
cis(−α)−cis(−θ)

=


cisα
cisβ

cisθ−cisβ
cisθ−cisα

.


By division


cis 2φ=

cisβ
cisα

=cis(β−α).

Thus 2(cisφ)^2 =(cisγ)^2 so that cisφ=±cisγ. Thus either cisφ=cisγor cisφ=


cis(γ+ (^180) F′),and accordingly



z 2 −z
z 1 −z

=lsinγ orℑ

z 2 −z
z 1 −z

=lsin(γ+ (^180) F′).
As sinγ> 0 ,the first of these occurs whenZis in the half-plane with edgeZ 1 Z 2 in
whichℑzz^21 −−zz> 0 ,and the second whenZis in the half-plane with edgeZ 1 Z 2 in which
ℑzz 12 −−zz< 0.

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