80 CHAPTER 2. MATHEMATICAL MODELS IN CONTROL
Then Equation (2.46) gives
x 1 (t)=−t+1 (2.49)
Therefore, the nominal trajectory for which Equations (2.46) and (2.47) are to
be linearized is described by
x 01 (t)=−t+1 (2.50)
x 02 (t)=1 (2.51)
Now evaluating the coefficients of Equation (2.45), we get
∂f 1 (t)
∂x 1 (t)=0
∂f 1 (t)
∂x 2 (t)=
2
x^32 (t)
∂f 1 (t)
∂u(t)=0
∂f 2 (t)
∂x 1 (t)=u(t)
∂f 2 (t)
∂x 2 (t)=0
∂f 2 (t)
∂u(t)=x^1 (t)
Using Equation (2.43), we get
4 x ̇ 1 (t)=
2
x^302 (t)
4 x 2 (t) (2.52)
4 x ̇ 2 (t)=u 0 (t) 4 x 1 (t)+x 01 (t) 4 u(t) (2.53)
Substituting Equations (2.50) and (2.51) into (2.52) and (2.53), we get
∑
4 x ̇ 1 (t)
4 x ̇ 2 (t)
∏
=
∑
02
00
∏∑
4 x 1 (t)
4 x 2 (t)
∏
+
∑
0
1 −t
∏
4 u(t) (2.54)
The set of Equations (2.54) represents linear state equations with time-varying
coefficients.
2.10Exercisesandprojects
- Show that the following systems are either linear or nonlinear, and either
time-varying or time-invariant.
(a)y(t)=v(t)dtd(v(t))
(b)
v(t)
−→ N 1
q(t)
−→ N 2
y(t)
−→whereN 1 andN 2 are linear systems connected
in cascade.
- Prove or disprove the following statements.
(a) In a linear system, if the response tov(t)isy(t), then the response
toRe(v(t))isRe(y(t))whereRe(x)denotes the real part of the
complex numberx.
(b) In a linear system, if the response tov(t)isy(t), then the response
todtd(v(t))isdtd(y(t)).