Answers to assignments 337
If we throw far, near, far, the probabilities
of throwing two in a row are as follows:
Hit, hit, miss:^13 ×^12 ×^23 =^218
Miss, hit, hit:^23 ×^12 ×^13 =^218
Hit, hit, hit:^13 ×^12 ×^13 =^118
The total probability of winning is^518
or about 28%. The second strategy is
better. Some may regard this as counter-
intuitive as it involves two throws at
the harder target. Did you expect this
answer? Can you rationalise why the
second strategy should be the best?
Can you prove that it works for all
probabilities (as long as the farther target
is harder to hit)?
4 We first need to do some calculations
on the various options. These are
summarised in the table on page 338,
with the second column showing the
figures for a machine achieving a 99%
detection rate and the third column
showing those for a machine achieving
a 95% detection rate. Fixed costs are
ignored; these figures just represent the
total income minus the quality control
costs for the different assumptions.
We can now construct the decision tree,
as shown below.
The differences are quite small – the
present system shows a saving of $830
in almost $1 million. However, the
automatic system carries an 80% chance
of the loss being $1750.
6.4 Have you solved it?
Variable responses
7.1 Conditions and conditionals
1 a Reading the book is a necessary but
not a sufficient condition for passing
the exam.
Automatic system
Stay with manual QC system
Detection rate 99%
Detection rate 95%
20% chance
80% chance
$936,750
$941,350
$938,500
Income Contribution
to expected
value
$188,270
$749,400
Overall expected value $937,670