7 CIRCULAR MOTION 7.5 Non-uniform circular motion
ss
=.,
=acts towards the centre of the circle. In other words,
T sin θ = m ω^2 r. (7.19)Taking the ratio of Eqs. (7.18) and (7.19), we obtainHowever, by simple trigonometry,
tan θ =ω^2 r
.
g(7.20)Hence, we find
tan θ =r. (7.21)
h
ω =g. (7.22)
h
Note that if l is the length of the string then h = l cos θ. It follows that
ωg. (7.23)
l cos θ
For instance, if the length of the string is l = 0.2 m and the conical angle isθ = 30 ◦ then the angular velocity of rotation is given by
ω‚
9.81
0.2 × cos 30 ◦= 7.526 rad./s. (7.24)This translates to a rotation frequency in cycles per second of
ω
f = = 1.20 Hz. (7.25)
2 π
7.5 Non-uniform circular motion
Consider an object which executes non-uniform circular motion, as shown in
Fig. 61. Suppose that the motion is confined to a 2-dimensional plane. We can
specify the instantaneous position of the object in terms of its polar coordinates r