8 ROTATIONAL MOTION 8.7 Torque
Figure 79: A rotating bicycle wheel.the tangential motion of the wheel, yields
M ̇v = f sin θ, (8.52)where M is the mass of the wheel (which is assumed to be concentrated in the
wheel’s rim).
Let us now convert the above expression into a rotational equation of motion.If ω is the instantaneous angular velocity of the wheel, then the relation between
ω and v is simply
v = b ω. (8.53)Since the wheel is basically a ring of radius b, rotating about a perpendicular
symmetric axis, its moment of inertia is
I = M b^2. (8.54)Combining the previous three equations, we obtain
where
I ω ̇ = τ, (8.55)τ = f b sin θ. (8.56)Equation (8.55) is the angular equation of motion of the wheel. It relates thewheel’s angular velocity, ω, and moment of inertia, I, to a quantity, τ, which is
known as the torque. Clearly, if I is analogous to mass, and ω is analogous to
f sin fO r^
P
b