11 OSCILLATORY MOTION 11.6 Uniform circular motionm 3Let f 1 = k 1 x 1 and f 2 = k 2 x 2 be the magnitudes of the forces exerted by the
first and second springs, respectively. Since the springs (presumably) possess
negligible inertia, they must exert equal and opposite forces on one another. This
implies that f 1 = f 2 , or
k 1 x 1 = k 2 x 2.
Finally, if f is the magnitude of the restoring force acting on the mass, then force
balance implies that f = f 1 = f 2 , orf = keff x = k 1 x 1.Here, keff is the effective force constant of the two springs. The above equationscan be^ combined^ to^ give^
keff =k 1 x 1
x 1 + x 2k 1
=
1 + k 1 /k 2k 1 k 2
=.
k 1 + k 2Thus, the problem reduces to that of a block of mass m = 3 kg attached to aspring^ of effective^ force^ constant^
keff =k 1 k 2
k 1 + k 2=1200 × 400
1200 + 400= 300 N/m.The angular frequency of oscillation is immediately given by the standard formulaω =‚
., keffHence, the period of oscillation is=‚
., 3002 π= 10 rad./s.T = = 0.6283 s.
ωk 1 k 2
m