GMAT Official Guide Quantitative Review 2019_ Book

GMAT® Official Guide 2019 Quantitative Review

PS 15753

62. A school club plans to package and sell dried fruit to
    raise money. The club purchased 12 containers of
    dried fruit, each containing 16¾ pounds. What is the
    maximum number of individual bags of dried fruit, each
    containing ¼ pounds, that can be sold from the dried
    fruit the club purchased?

(A) 50

(Bl 64

(C) 67

(D) 768

(E) 804

Arithmetic Applied problems; Operations with

factions

The 12 containers, each containing 161 pounds

4

of dried fruit, contain a total of (12) ( 16 ¾) =

(12) (^6 :) = (3)(67) = 201 pounds of dried fruit,

which will make^2 ~^1 = (201)(4) = 804 individual

4

bags that can be sold.

The correct answer is E.

/"Height Price \

Less than 5 ft $14.95

5 ft to 6 ft $17.95

\.. Over 6 ft $21.95

PS02498

63. A nursery sells fruit trees priced as shown in the chart
    above. In its inventory 54 trees are less than 5 feet
    in height. If the expected revenue from the sale of its
    entire stock is estimated at $2,450, approximately
    how much of this will come from the sale of trees that
    are at least 5 feet tall?

(A) $1,730

(B) $1,640

(Cl $1,410

(D) $1,080

(E) $810

Arithmetic Applied problems

If the nursery sells its entire stock of trees, it

will sell the 54 trees that are less than 5 feet in

height at the price per tree of $14.95 shown in

the chart .. The expected revenue from the sale of

the trees that are less than 5 feet tall is therefore

54 X $14. 95 = $807.30. The revenue from the sale

of the trees that are at least 5 feet tall is thus equal

to the total revenue from the sale of the entire

stock of trees minus $807.30. The revenue from

the sale of the entire stock of trees is estimated at

$2,450. Based on this estimate, the revenue from

the sale of the trees that are at least 5 feet tall

will be $2,450 - $807.30 = $1,642.70, which is

approximately $1,640.

The correct answer is B.

PS10539

64. The sequence a 1 , a 2 , a 3 , a 4 , a 5 is such that
    an= an_ 1 + 5 for 2:::; n:::; 5. If a 5 = 31, what is the
    value of a 1?

(A) 1

(B) 6

(C) 11

(D) 16

(El 21

Algebra ~ JE" c

Since an== a n-1 + 5, then a n - a n-1 = 5. So,

a 5 -a 4 = 5

a 4 -a 3 = 5

a 3 -a 2 = 5

a 2 -a 1 = 5

Adding the equations gives

a 5 - a 4 + a 4 - a 3 + a 3 - a 2 + a 2 - a 1 = 5 + 5 + 5 + 5

a 5 -a 1 = 20

and substituting 31 for a 5 gives

31-al = 20

a 1 = 11.

The correct answer is C.