GMAT Official Guide Quantitative Review 2019_ Book

(singke) #1
4.5 Answer Explanations

PS00904 �
134.The figure shown above consists of three identical
circles that are tangent to each other. If the area of the
shaded region is 64岛-32冗,what is the radius of
each circle?
(A) 4
(8)^8
(Cl 16
(D)^24
(El 32


Geometry
Let r represent the radius of each circle. Then the
triangle shown dashed in the figure is equilateral
with sides 2r units long. The interior of the
triangle is comprised of the shaded region and
three circular sectors. The area of the shaded
region can be found as the area of the triangle
minus the sum of the areas of the three sectors.
Since the triangle is equilateral, 兀sside lengths
are in the proportions as shown in the diagram
below. The area of the interior of the triangle is

炉r)(r句=r飞.


r r

讨5
2r

Each of the three sectors has a central angle of
60 ° because the central angle is an angle of the
equilateral triangle. Therefore, the area of each
60 1
sector is—= -of the area of the circle. The
360 6
sum of the areas of the three sectors is then
3(.!. 冗r^2 )=.!.冗r^2. Thus, the area of the shaded
6 2

region is r^2 喜;矿=r^2 (.Jj卡)But, this

area is given as 64.Ji -32冗= 64 (.Ji卡).

Thus r2 = 64, and r = 8.

Th e correct answer 1s B.
PS02053


  1. In a numerical table with 10 rows and 10 columns,
    each entry is either a 9 or a 10. If the number of 9s in
    the nth row is n - l for each n from 1 to 10, what is
    the average (arithmetic mean) of all the numbers in the
    table?


(A) 9. 45
(B) 9. 50
(C) 9. 55
(D) 9. 65
(El 9.70
Arithmetic
There are (10)(10) = 100 entries in the table. In
rows 1, 2, 3, ... , 10, the number of 9s is 0, 1, 2, ... ,
9, respectively, giving a total of O + 1 + 2 + ... + 9 =
45 entries with a 9. This leaves a total of
100 - 45 = 55 entries with a 10. Therefore, the
sum of the 100 entries is 45(9) + 55(10) =
405 + 550 = 955, and the average of the
100

.. 955
entnes 1s—= 9.55
100
Th e correct answer 1s C.
PS08485
136. A pos巾ve integer n is a perfect number provided that
the sum of all the positive factors of n, including 1 and
n, is equal to 2n. What is the sum of the reciprocals of
all the positive factors of the perfect number 28?


(Al

1-4

(Bl

56
27
(Cl 2
(Dl^3
(El^4
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