GMAT® Official Guide 2019 Quantitative Review
on the order is ( 1+-r-)($0.105n). Given that
100(^1 +-r 100 -) ($0.105n) = $44.10, what is the value
of (-r-)($0.105n)?
100(1) Given that r = 5, then ( 1 +
1;
0) ($0.105 n)= $44.10 becomes (1.05)(0.105n) = 44.10,
which is a first- degree equation that can be
solved for n. Since the value of r is known
and the value of n can be determined, itfollows that the value of (-r- ) ($0.105n)
100
can be determined; SUFFICIENT.(2) Given that n = 400, then
(^1 + - r 100 -)($0.105n) = $44.10 becomes
(^1 + - r- )(0 100 .105)(400) = 44.10, which is a
first- degree equation that can be solved
for r. Since the value of r can be determined
and the value of n is known, it followsthat the value of ( - r- ) ($0.105n) can be
100
determined; SUFFICIENT.
The correct answer is D;
each statement alone is sufficient.
DS06785- If m is an integer greater than 1, is m an even integer?
(1) 32 is a factor of m.
(2) m is a factor of 32.Arithmetic Properties of numbers
(1) Given that 32 is a factor of m, then each of
the factors of 32, including 2, is a factor of m.
Since 2 is a factor of m, it follows that mis
an even integer; SUFFICIENT.
(2) Given that mis a factor of 32 and m is
greater than 1, it follows that m = 2, 4, 8, 16,
or 32. Since each of these is an even integer,
m must be an even integer; SUFFICIENT.
The correct answer is D;
each statement alone is sufficient.DS056 57
22 7. If t he set S consists of five consecutive positive
integers, what is the sum of these five integers?(1) The integer 11 is in S, but 10 is not in S.
(2) The sum of the even integers in S is 26.Arithmetic Sequences
(1) This indicates that the least integer in
S is 11 since S consists of consecutive
integers and 11 is in S, but 10 is not in S.
Thus, the integers in Sare 11, 12, 13, 14,
and 15, and their sum can be determined;
SUFFICIENT.
(2) This indicates that the sum of the even
integers in Sis 26. In a set of 5 consecutive
integers, either two of the integers or three of
the integers are even. If there are three even
integers, then the first integer in S must be
even. Also, since^26 = s l , the three even
3 3
integers must be around 8. The three even
integers could be 6, 8, and 10, but are not
because their sum is less than 26; or they
could be 8, 10, and 12, but are not because
their sum is greater than 26. Therefore, S
cannot contain three even integers and
must contain only two even integers. Those
integers must be 12 and 14 since 12 + 14
= 26. It follows that the integers in Sare
11, 12, 13, 14, and 15, and their sum can be
determined; SUFFICIENT.
Alternately, if n, n + l, n + 2, n + 3, and n + 4
represent: the five consecutive integers and three
of them are even, then n + (n + 2) + (n + 4) = 26,
or 3n = 20, or n =^20 , which is not an integer.
3
On the other hand, if two of the integers are
even, then (n + 1) + (n + 3) = 26, or 2n = 22, or
n = 11. lt follows that the integers are 11, 12, 13,
14, and 15, and their sum can be determined;
SUFFICIENT.The correct answer is D;
each sta11:ement alone is sufficient.
DSI 7543- If x > 0, what is the value of x?
(1) x^3 -x= 0
(2) ~ - x=O