GMAT® Official Guide 2019 Quantitative Review
Example 2: If Art and Rita can do a job in 4 hours when working together at their respective constant
rates and Art can do the job alone in 6 hours, in how many hours can Rita do the job alone?
Solution:
1+_1=1
6 R 4
R+6 l
6R 4
4R+24=6R
24 =2R
l2= R
Working alone, Rita can do the job in 12 hours.
- Mixture Problems
In mixture problems, substances with different characteristics are combined, and it is necessary to
determine the characteristics of the resulting mixture.
Example 1: If 6 pounds of nuts that cost $1.20 per pound are mixed with 2 pounds of nuts^1 hat cost
$1.60 per pound, what is the cost per pound of the mixture?
Solution: The total cost of the 8 pounds of nuts is
The cost per pound is
6($1.20) + 2($1.60) = $10.40.
$10.40 = $1.30.
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Example 2: How many liters of a solution that is 15 percent salt must be added to 5 liters of a solution
that is 8 percent salt so that the resulting solution is 10 percent salt?
Solution: Let n represent the number ofliters of the 15% solution. The amount of salt in the 15%
solution [0.15n] plus the amount of salt in the 8% solution [(0.08)(5)] must be equal to the amount of
salt in the 10% mixture [0.lO(n + 5)]. Therefore,
0.l5n + 0.08(5) = 0.l0(n + 5)
l5n+40 = l0n+50
5n = 10
n = 2 liters
Two liters of the 15% salt solution must be added to the 8% solution to obtain the 10% solution.
- Interest Problems
Interest can be computed in two basic ways. With simple annual interest, the interest is computed on
the principal only and is equal to (principal) x (interest rate) x (time). If interest is compounded, then
interest is computed on the principal as well as on any interest already earned.