McGraw-Hill Education GRE 2019

SOLUTION: Based on Property 4, you should multiply the average and the

number of items in the set. From Property 2, you know that the average of

an evenly spaced set equals the average of the endpoints: 180 + 4 2 = 92. Using

Property 3, you can determine the number of items:

180 – 4

2 + 1 = 89

SOLUTION: A × N = S, so 92 × 89 = S = 8,188.

Quantitative Comparison Strategy: Evenly Spaced Sets

Many Quantitative Comparison questions testing evenly spaced sets will give you

large sets of values. As is always the case with Quantitative Comparison questions,

you should minimize calculations by comparing the quantities and identifying

what terms they have in common:

QUANTITY A QUANTITY B

A B C D

SOLUTION: Instead of calculating, identify similarities between the two

columns.

Quantity A can be rewritten as: (1 + 2 + 3... 6) + (7 + 8... 28).

Quantity B can be rewritten as: (7 + 8... 28) + 29.

SOLUTION: The two quantities share the sum of the terms from 7–28, inclusive.

You can thus subtract this sum from both quantities. The new comparison is:

QUANTITY A QUANTITY B

1 + 2 + 3 + 4 + 5 + 6 29 A B C D

SOLUTION: The value in Quantity A = 21. 21 < 29, so Quantity B is greater.

The sum of the

in tegers from 1–28,

inclusive

The sum of the

integers from 7–29,

inclusive

200 PART 4 ■ MATH REVIEW

03-GRE-Test-2018_173-312.indd 200 23/01/18 11:03 AM