- E Recognize that^23 = 0.66
Now compare the choices:
Choice A: 45 = 0.8 > 0.66 → Eliminate A.
Choice B: 2718 =^23 , so^1927 >^23 → Eliminate B.
Choice C: 1015 =^23 , so^1115 >^23 → Eliminate C.
Choice D: 3450 = 10068 = 0.68 > 0. 66 → Eliminate D.
Choice E: 35 = 0.6 < 0. 66 → E is the answer. - –2 Express 1.5 × 104 as 15,000. To go from 15,000 to 150, you must move the
decimal two places to the left. Thus x = –2. - C Bob accidentally moved the decimal two places to the right instead of
two places to the left. To correct the original error, he needs to first move the
decimal two places to the left to arrive at 3.87. To do the correct calculation, he
must move the decimal two places to the left again, to arrive at 0.0387.
Quantitative Comparison Questions
- C Add the fractions in Quantity A by finding a common denominator of xy.
1
x ×
y
x =y
xy
1
y ×x
x =x
xy
Thus^1 x +^1 y = xyy + xyx = y + xxy. The two quantities are equal.- D Choose values for x. The best numbers to consider are 0, 1, and –1. If x = 1,
then Quantity A is greater. If x = 0, then the denominator of both quantities
will equal 1 and the two fractions will therefore be equal. Since a relationship
cannot be determined, the answer is Choice D. - A Since x is greater than y, and^13 is greater than^14 , the value in Quantity A
will be a bigger piece of a bigger whole than the value in Quantity B. Thus
Quantity A is greater. - B To simplify the comparison, divide both quantities by 200. The new
comparison is thus:
QUANTITY A QUANTITY B
13 × 75 ×^34 1,200 × ( 151 ) (^14 ) A B C D
Next, reduce both quantities:
Quantity A:^13 × 75 = 25, so Quantity A = 25 ×^34
Quantity B:^14 × 1,200 = 300
300 × 151 = 15 × 20 15 = 20
3
4 × 25 < 20. Quantity B is greater.
226 PART 4 ■ MATH REVIEW03-GRE-Test-2018_173-312.indd 226 12/05/17 11:52 am