(you can’t have a fraction of a student!) and this integer = 20x, the number of
students in the school must be a multiple of 20. Of the choices, the only value
that is not a multiple of 20 is 90.- E Since you are not given a value for either part, represent the parts
algebraically:
ounces of alcohol = 1x and ounces of water 8x
In terms of x, the volume of the solution is 1x + 8x = 9x. Since the solution is
31.5 ounces,
9 x = 31. 5
x = 3.5
The number of ounces of water is 8x = 8(3.5 ounces) = 28 ounces. The correct
answer is Choice E. - D Since you are not given a value for either quantity, represent the values
algebraically:
number of managers/number of directors =^53 =^53 xx
You are told that 10 managers will become directors. Thus after the change,
the number of managers will be 5x – 10, and the number of directors will be
3 x + 10. Use these values for the second ratio in the question:
new number of managers/new number of directors =^75 =^53 xx – 10 + 10
Cross-multiply to solve:
75 =^53 xx – 10 + 10
7(3x + 10) = 5(5x – 10)
21 x + 70 = 25x – 50
120 = 4x
x = 30
The original number of managers is 5x. Plug in 30 for x: 5(30) = 150. - C Since the question provides ratios with no actual values, represent the
quantities algebraically:
number of cello players
number of viola players =
4 x
5 x
Since the number of viola players = 2 + number cello players, create the
equation: 5x = 4x + 2. Solve for x: x = 2. The number of viola players is 5x.
Plug in 2 for x. The answer is 5(2) = 10.- C Since the question provides ratios with no actual values, represent each part
of the budget algebraically:
4 x = amount budgeted for advertising
3 x = amount budgeted for product development
x = amount budgeted for administration
CHAPTER 10 ■ PART-TO-WHOLE RELATIONSHIPS 25303-GRE-Test-2018_173-312.indd 253 12/05/17 11:53 am