Next, evaluate the exponential term: 12^2 = 14 4
–2(–2) ÷ 144Since multiplication is to the left of division, multiply –2 × –2 = 4.
4 ÷ 144Next, do the division: 14 4^4 = 361.- B Solution: Add up the equations:
4 a + 4b + 4c = 40
4(a + b + c) = 40
a + b + c = 10 - B Solution: note that the two expressions share the common term of (x + b).
Combine like terms and arrive at 8(x + b) = 72. Divide both sides of the
equation by 8: x + b = 9. - E You should always attempt to simplify equations, if possible. In the
second equation, you can factor 2 from all the terms: 2(3b + 5c) = 20. Divide
both sides by 2: 3b + 5c = 10. Substitute 10 for 3b + 5c in the first equation:
a + 10 = 30. Solve for a: a = 20. Therefore, 4a = 80. - C To solve for y in terms of x, you must isolate y. First, get rid of the square
root by squaring both sides of the equation: y + 3 2 = x^2. Next, multiply both
sides by 2: y + 3 = 2x^2. Then subtract 3 from both sides: y = 2x^2 − 3. The correct
answer is C. - −7 3 Since you are trying to solve for an expression that has y and x, manipulate
the equation to get the xs and ys on the same side: 3x − 12y = −7. Factor
3 from both terms on the right side of the equation: 3(x − 4y) = −7. Solve for
x − 4y: x − 4y = −7 3.
Quantitative Comparison Questions
- C
Step 1: To make the columns look similar, try to factor the expression in
Quantity A:
pr + qr = r(p + q) and qs + ps = s(q + p).
Step 2: Combine like terms: r(p + q) + s(q + p) = (r + s)(p + q).
The two quantities are equal. - C
Step 1: To avoid working with a fraction, multiply both sides of the given
equation by 7: xz = 7y
Step 2: To make the columns look similar, substitute 7y for xz in Quantity B:
7(7y) = 49y
The two quantities are equal.
268 PART 4 ■ MATH REVIEW03-GRE-Test-2018_173-312.indd 268 12/05/17 11:54 am