Thus
25 y × 5 = 24
2 y = 24
y = 12Quantitative Comparison Questions
- B Since Sally spends half of the distance of the trip traveling 50 miles per
hour, and the other half of the distance of the trip traveling 40 miles per hour,
she must spend more time traveling 40 miles per hour than 50 miles per hour.
Her average speed must therefore be closer to 40 than to 50. Since 45 is the
midpoint of 40 and 50, her average speed must be less than 45. - D Dennis cooks cakes at a rate of hourscakes = x 3. He cooks pies at a rate of hourspies = 0.5y.
y
0.5 =
y
1
2=^21 y. Use the r × t = w table to arrive at a value for each of the
quantities.Quantity 1: r × t = w
↓x 3 × 6 = 2x
Quantity 2: r × t = w
↓
2 y × 3 = 6y
If x = 6 and y = 2, then the two quantities are equal. If x = 6 and y = 1, then
Quantity A is greater. A relationship cannot be determined.- C Jake’s rate is minuteslap =^1 x. Double that rate would be^2 x. To solve for how long it
would take him to run a lap at this rate, use the r × t = d table:
(^2) x × t = 1
t = x 2
The two quantities are equal.
- B If Car A is 80 miles from its starting point when the cars meet, then Car B
is 120 miles from its starting point. Since the cars traveled for the same time
and Car B traveled a greater distance, Car B’s rate must have been greater. - D From the given information, you can infer that Car A traveled 25 more
miles than Car B. However, Car A could have traveled a total of 26 miles or
a total of 31 miles. Thus the relationship between the quantities cannot be
determined. - D Without knowing the capacity of the tank, you cannot determine the
amount of time it will take to fill the tank. - C The combined rate of the eight machines is computers/hours =^76. Note
that a rate of 21 computers18 hours reduces to 7 computers6 hours. Thus the number of machines
necessary to produce 21 computers in 18 hours equals the number of
computers necessary to produce 7 computers in 6 hours.
354 PART 4 ■ MATH REVIEW04-GRE-Test-2018_313-462.indd 354 12/05/17 12:04 pm