MCAT Organic Chemistry Review 2018-2019

(singke) #1
The Strecker    synthesis   creates an  amino   acid    from    an  aldehyde.   The carbonyl    carbon  ultimately
becomes the α-carbon of the amino acid. Any remaining alkyl chain becomes the R group, as
shown below. The starting compound is therefore 2-methylpropanal (isobutyraldehyde).

7 . D


One resonance   structure   of  a   C–N bond    in  an  amide   has the double  bond    between the C   and N,
not between the C and O. Thus, the C–N bond of an amide has some sp^2 character, and sp^2 -
hybridized atoms exhibit planar geometry.

8 . D
Both the Strecker and Gabriel syntheses contain planar intermediates, which can be attacked
from either side by a nucleophile. This results in a racemic mixture of enantiomers, and the
solution will therefore be optically inactive.

9 . A
During the Gabriel synthesis, phthalimide attacks a secondary carbon in diethyl bromomalonate.
The secondary carbon is the electrophile, choice (D), and bromide is the leaving group, choice
(C).

10 . C
The Gabriel synthesis includes two nucleophilic substitution steps, followed by hydrolysis and
decarboxylation. Dehydration—the loss of a water molecule—is not a part of this reaction.


11 . B


The pKa 2   of  phosphoric  acid    is  close   to  physiological   pH; therefore,   at
this pH.

12 . C
Pyrophosphate is unstable in aqueous solution and will degrade to form two equivalents of
inorganic phosphate. The solvent is water, which should retain its polarity regardless of the

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