ffirs.indd

(Brent) #1

Long Division by Factors 143
We now divide 6 into 54. What do we multiply by 6 to get an
answer of 54? Th e answer is 9. Nine times 6 is exactly 54, so we
write 9 and carry no remainder.
Now we have one digit left to divide. Zero divided by 6 is 0, so we
write 0 as the fi nal digit of the fi rst answer. Our calculation looks
like this:
6 3 90
6 2,3^540
Now we divide our answer, 390, by the second 6.
Six divides into 39 six times with 3 remainder (6 × 6 = 36). Write 6
above the 9 and carry the 3 remainder to make 30.
6
6 3 9^30
6 2,3^540
Six divides into 30 exactly 5 times, so the next digit of the answer is



  1. Our answer is 65 with no remainder.
    Depending on which layout you use, your fi nal calculation would
    look like one of these:
    6 5 6 2,3^5 4 0
    6 3 9^3 0 6 3 9^30
    6 2,3^5 4 0 6 5
    What are some other factors we could use? To divide by 48, we
    could divide by 6, then by 8 (6 × 8 = 48).
    To divide by 25, we would divide by 5 twice (5 × 5 = 25).
    To divide by 24, we could divide by 4, then by 6 (4 × 6 = 24). Or
    we could divide by 3, then by 8, or we could halve the number and
    then divide by 12.

Free download pdf