Transposing formulae 89
Rearranging gives
√(
f+p
f−p
)
=
D
d
Squaring both sides gives
(
f+p
f−p
)
=
D^2
d^2
Cross-multiplying,i.e. multiplyingeach term
byd^2 (f−p),gives
d^2 (f+p)=D^2 (f−p)
Removing brackets gives d^2 f+d^2 p=D^2 f−D^2 p
Rearranging, to obtain terms inpon the LHS gives
d^2 p+D^2 p=D^2 f−d^2 f
Factorizing gives p(d^2 +D^2 )=f(D^2 −d^2 )
Dividing both sides by(d^2 +D^2 )gives
p=
f(D^2 −d^2 )
(d^2 +D^2 )
Now try the following Practice Exercise
PracticeExercise 48 Further transposing
formulae (answers on page 345)
Make the symbol indicated the subject of each of
the formulae shown in problems 1 to 7 and express
each in its simplest form.
- y=
a^2 m−a^2 n
x
(a)
- M=π(R^4 −r^4 )(R)
- x+y=
r
3 +r
(r)
- m=
μL
L+rCR
(L)
- a^2 =
b^2 −c^2
b^2
(b)
6.
x
y
=
1 +r^2
1 −r^2
(r)
7.
p
q
=
√(
a+ 2 b
a− 2 b
)
(b)
- A formula for the focal length,f,ofaconvex
lens is
1
f
=
1
u
+
1
v
. Transpose the formula to
makevthe subject and evaluatevwhenf= 5
andu=6.
9. Thequantityofheat,Q,isgivenbytheformula
Q=mc(t 2 −t 1 ).Maket 2 the subject of the
formula and evaluatet 2 whenm=10,t 1 =15,
c=4andQ=1600.
10. The velocity,v, of water in a pipe appears
in the formula h=
0. 03 Lv^2
2 dg
. Express v
as the subject of the formula and evalu-
atevwhenh= 0. 712 ,L= 150 ,d= 0 .30 and
g= 9. 81
11. The sag,S, at the centre of a wire is given
by the formulaS=
√(
3 d(l−d)
8
)
.Makel
the subject of the formula and evaluatelwhen
d= 1 .75 andS= 0 .80.
- In an electrical alternating current cir-
cuit the impedance Z is given by
Z=
√√
√
√
{
R^2 +
(
ωL−
1
ωC
) 2 }
. Transpose
the formula to makeCthe subject and hence
evaluateCwhenZ= 130 ,R= 120 ,ω= 314
andL= 0. 32
- An approximate relationship between the
number of teeth,T, on a milling cutter, the
diameter of cutter,D, and the depth of cut,d,
is given byT=
12. 5 D
D+ 4 d
. Determine the value
ofDwhenT=10 andd=4mm.
14. Makeλ, the wavelength ofX-rays, the subject
of the following formula:
μ
ρ
=
CZ^4
√
λ^5 n
a