Basic Engineering Mathematics, Fifth Edition

(Amelia) #1

Areas of common shapes 227


inthe middleof the garden. Find, correct tothe
nearest square metre, the area remaining.


  1. Determine the area of circles having (a) a
    radius of 4cm (b) a diameter of 30mm (c) a
    circumference of 200mm.

  2. An annulus has an outside diameter of 60mm
    and an inside diameter of 20mm. Determine
    its area.

  3. If the area of a circle is 320mm^2 , find (a) its
    diameter and (b) its circumference.

  4. Calculate the areas of the following sectors of
    circles.
    (a) radius 9cm, angle subtended at centre
    75 ◦.
    (b) diameter 35mm, angle subtended at
    centre 48◦ 37 ′.

  5. Determine the shaded area of the template
    shown in Figure 25.23.


120mm

90mm

80mm
radius

Figure 25.23


  1. An archway consists of a rectangular opening
    topped by a semi-circular arch, as shown in
    Figure 25.24. Determine the area of the open-
    ing if the width is 1m and the greatest height
    is 2m.


1m

2m

Figure 25.24

Here are some further worked problems of common
shapes.


Problem 17. Calculate the area of a regular
octagon if each side is 5cm and the width across the
flats is 12cm

An octagon is an 8-sided polygon. If radii are drawn
from the centre of the polygon to the vertices then 8
equal triangles are produced, as shown in Figure 25.25.

12cm

5m

Figure 25.25

Area of one triangle=

1
2

×base×height

=

1
2

× 5 ×

12
2

=15cm^2

Area of octagon= 8 × 15 =120cm^2

Problem 18. Determine the area of a regular
hexagon which has sides 8cm long

A hexagon is a 6-sided polygon which may be divided
into 6 equal triangles as shown in Figure 25.26. The
angle subtended at the centre of each triangle is 360◦÷
6 = 60 ◦. The other two angles in the triangle add up to
120 ◦and are equal to each other. Hence, each of the
triangles is equilateral with each angle 60◦and each
side 8cm.
4cm

8cm

8cm

608

h

Figure 25.26

Area of one triangle=

1
2

×base×height

=

1
2

× 8 ×h
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