Basic Engineering Mathematics, Fifth Edition

(Amelia) #1

58 Basic Engineering Mathematics


Hence, 42× 105 = 4. 2 × 106 in engineering
notation
=4.2 Min prefix form.

(b) Enter 47÷ 1010 =

47
10000000000

into the calcu-
lator. Press=
NowpressENGandtheansweris4. 7 × 10 −^9.
From the table of prefixes on page 55, 10−^9
corresponds to nano.
Hence, 47÷ 1010 F=4.7× 10 −^9 Fin engineer-
ing notation
=4.7nFin prefix form.

Problem 8. Rewrite (a) 0.056mA inμA
(b) 16700kHz as MHz

(a) Enter 0. 056 ÷1000 into the calculator (since milli
means÷1000). Press=
Now press ENG and the answer is 56× 10 −^6.
From the table of prefixes on page 55, 10−^6
corresponds to micro.

Hence, 0.056mA=

0. 056
1000

A= 56 × 10 −^6 A
= 56 μA.

(b) Enter 16700×1000 into the calculator (since kilo
means×1000). Press=
Now press ENG and the answer is 16. 7 × 106.
From the table of prefixes on page 55, 10^6 corre-
sponds to mega.

Hence, 16700kHz= 16700 ×1000Hz

= 16. 7 × 106 Hz
=16.7MHz

Problem 9. Rewrite (a) 63× 104 VinkV
(b) 3100pF in nF

(a) Enter 63× 104 into the calculator. Press=
Now press ENG and the answer is 630× 103.
From the table of prefixes on page 55, 10^3 corre-
sponds to kilo.
Hence, 63× 104 V= 630 × 103 V=630kV.

(b) Enter 3100× 10 −^12 into the calculator. Press=
Now press ENG and the answer is 3. 1 × 10 −^9.
From the table of prefixes on page 55, 10−^9
corresponds to nano.
Hence, 3100pF= 31 × 10 −^12 F= 3. 1 × 10 −^9 F
=3.1 nF

Problem 10. Rewrite (a) 14700mm in metres
(b) 276cm in metres (c) 3.375kg in grams

(a) 1m=1000mm, hence
1mm=

1
1000

=

1
103

= 10 −^3 m.

Hence, 14700mm= 14700 × 10 −^3 m= 14 .7m.

(b) 1m=100cm, hence 1cm=
1
100

=
1
102

= 10 −^2 m.

Hence, 276cm= 276 × 10 −^2 m= 2 .76m.
(c) 1kg=1000g= 103 g
Hence, 3.375kg= 3. 375 × 103 g=3375g.

Now try the following Practice Exercise

PracticeExercise 34 Engineering notation
(answers on page 343)

In problems 1 to 12, express in engineering nota-
tion in prefix form.


  1. 60000Pa

  2. 0.00015W

  3. 5× 107 V



    1. 5 × 10 −^8 F



  4. 100000W

  5. 0.00054A

  6. 15× 105 

  7. 225× 10 −^4 V

  8. 35000000000Hz



    1. 5 × 10 −^11 F



  9. 0.000017A

  10. 46200

Free download pdf