84 Basic Engineering Mathematics
Rearranging gives^2 gh=v^2
Dividing both sides by 2ggives
2 gh
2 g
=
v^2
2 g
Cancelling gives h=
v^2
2 g
Problem 5. IfI=
V
R
, rearrange to makeVthe
subject
I=
V
R
is Ohm’s law, whereIis the current,Vis the
voltage andRis the resistance.
Rearranging gives V
R
=I
Multiplying both sides byRgives R
(
V
R
)
=R(I)
Cancelling gives V=IR
Problem 6. Transposea=
F
m
form
a=
F
m
relates accelerationa,forceFand massm.
Rearranging gives F
m
=a
Multiplying both sides bymgivesm
(
F
m
)
=m(a)
Cancelling gives F=ma
Rearranging gives ma=F
Dividing both sides byagives
ma
a
=
F
a
i.e. m=F
a
Problem 7. Rearrange the formulaR=
ρL
A
to
make (a)Athe subject and (b)Lthe subject
R=
ρL
A
relates resistanceRof a conductor, resistiv-
ityρ, conductor lengthLand conductor cross-sectional
areaA.
(a) Rearranging gives
ρL
A
=R
Multiplying both sides byAgives
A
(
ρL
A
)
=A(R)
Cancelling gives ρL=AR
Rearranging gives AR=ρl
Dividing both sides byRgives
AR
R
=
ρL
R
Cancelling gives A=
ρL
R
(b) Multiplying both sides of
ρL
A
=RbyAgives
ρL=AR
Dividing both sides byρgives
ρL
ρ
=
AR
ρ
Cancelling gives L=
AR
ρ
Problem 8. Transposey=mx+cto makemthe
subject
y=mx+cis the equation of a straight line graph,
whereyis the vertical axis variable,xis the horizontal
axis variable,mis the gradient of the graph andcis the
y-axis intercept.
Subtractingcfrom both sides gives y−c=mx
or mx=y−c
Dividing both sides byxgives m=
y−c
x
Now try the following Practice Exercise
PracticeExercise 46 Transposing formulae
(answers on page 344)
Make the symbol indicated the subject of each of
theformulaeshown and express each in its simplest
form.
- a+b=c−d−e (d)
- y= 7 x (x)
- pv=c (v)
- v=u+at (a)
- V=IR (R)
- x+ 3 y=t (y)
- c= 2 πr (r)
- y=mx+c (x)