A graphical design solution, to determine the earth thrust (P)
behind a retaining wall. Data from previous page:
h = 3„300 m
=30°
w = 1500 kg/m^3
Wall height is drawn to scale and plane of repose plotted. The
wedge section is obtained by drawing the plane of rupture through
an angle bisecting the plane of repose and vertical back of the
wall. Dimension `y' can be scaled or calculated:
Tangent x =
y
3„3 x=30
;and tan 30= 0„5774
therefore, y = 3„3 ¾ 0„5774 = 1„905 m
Area of wedge section =3„3 2 ¾1„905 m = 3„143 m^2
Volume of wedge per metre run of wall = 3„143 x 1 = 3„143 m^3
Weight .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. = 3„143 ¾ 1500 = 4715 kg
Vector line A † B is drawn to a scale through centre of gravity of
wedge section, line of thrust and plane of rupture to represent
4715 kg.
Vector line B † C is drawn at the angle of earth friction (usually
same as angle of repose, i.e. 30°in this case), to the normal to the
plane of rupture until it meets the horizontal line C † A.
Triangle ABC represents the triangle of forces for the wedge
section of earth, so C † A can be scaled at 2723 kg to represent
(P), the earth thrust behind the retaining wall.
Retaining Walls---Coulomb’s Wedge Theory