Answers 235These are the two cases between five and six, and the latter will, of course, be
the sooner.
- WESTMINSTER CLOCK
The times were 8 hours 237 lt\43 minutes, and 4 hours 4113 VI43 minutes. We
are always allowed to assume that these fractional times can be indicated in
clock puzzles.
- HILL CLIMBING
It must have been 63 /.1 miles to the top of the hill. He would go up in
4~ hours and descend in I ~ hours.- TIMING THE CAR
As the man can walk 27 steps while the car goes 162, the car is clearly going
six times as fast as the man. The man walks 3 ~ miles an hour: therefore the
car was going at 21 miles an hour.58. THE STAIRCASE RACE
If the staircase were such that each man would reach the top in a certain
number of full leaps, without taking a reduced number at his last leap, the
smallest possible number of steps would, of course, be 60 (that is, 3 X 4 X 5).
But the sketch showed us that A. taking three steps at a leap, has one
odd step at the end; B. taking four at a leap, will have three only at the end;
and C. taking five at a leap, will have four only at the finish. Therefore, we
have to find the smallest number that, when divided by 3, leaves a remainder I,
when divided by 4 leaves 3, and when divided by 5 leaves a remainder 4. This
number is 19. So there were 19 steps in all, only 4 being left out in the sketch.
- A WALKING PUZZLE
It will be found (and it is the key to the solution) that the man from
B. can walk 7 miles while the man from A. can walk 5 miles. Say the distance
between the towns is 24 miles, then the point of meeting would be 14 miles