Answers 237Anderson ride at the start. Anderson will then ride each of his five stages in
% hour and walk each of his four stages in % hour, making rus total time 3 Y.!
hours. Brown will ride each of his four stages in ~18 hour and walk each of his
five stages in '!-9 hour, making his total time also 3 Y.! hours. The distances that
Anderson and Brown ride respectively must be in the proportion of 5 to 4;
the distances they walk in the proportion of 4 to 5.
- MORE BICYCLING
A. rides 71 Y:17 miles, B. rides l^13 b miles, and C. rides I Ph7 miles, making
the 20 miles in all. They may ride in any order, only each man should com-
plete his ride in one mount and the second rider must always walk both before
and after riding. They will each take 3% hours on the journey, and therefore
will all arrive together.
- A SIDECAR PROBLEM
Atkins takes Clarke 40 miles in his car and leaves him to walk the remain-
ing 12 miles. He then rides back and picks up Baldwin at a point 16 miles
from the start and takes him to their destination. All three arrive in exactly
5 hours. Or Atkins might take Baldwin 36 miles and return for Clarke, who
will have walked his 12 miles. The sidecar goes 100 miles in all, with no pas-
senger for 24 miles.
- THE DISPATCH RIDER
The answer is the square root of twice the square of 40, added to 40. This
is 96.568 miles, or, roughly, 96~ miles.
- THE TWO TRAINS
In 5 seconds both trains (together) go 600 feet, or 81'¥t1 miles per hour. In
15 seconds the faster train gains 600 feet, or 273 ft 1 miles per hour. From this
we get 540/11 miles per hour as the rate of the faster train; and it is clear that
273 ft 1 miles per hour is the rate of the other.