244 Answers
- A QUESTION OF TRANSPORT
The car should take four men 12 miles, and drop them 8 miles from their
destination; then return 8 miles and pick up four men from the eight who have
walked to that point; then proceed 12 miles, and drop the second four 4 miles
from destination; then return 8 miles and pick up the last four, who will be
8 miles from the starting point; then drive these 12 miles to their destination,
where all will arrive at the same time. The car has thus gone 52 miles, which
would take 23 /s hours. The time of arrival was, therefore, 2:36 P.M.
- HOW FAR WAS IT?
The distance must have been 300 miles.
- OUT AND HOME
The distance must be 13 Ii miles, so that he walked into the town in 2%
hours and returned in 4% hours, making 7 hours, as stated.
- THE MEETING CARS
The distance from London to Bugleminster must be 72 miles.
- A BICYCLE RACE
They will come together 12 minutes from the start.
- A LITTLE TRAIN PUZZLE
There is no necessity for any algebraical working in the solution of this
problem, nor need we know the distance between the two stations. Wherever
they meet, just send the two trains back for an hour's journey at their respec-
tive rates. One will obviously go 60 miles and the other 40 miles, so they were
100 miles (60 added to 40) apart an hour before they met!
- AN IRISH JAUNT
After travelling 20 minutes Pat said we had gone just half as far as the re-