536 Puzzles and Curious Problems

(Elliott) #1
246 Answers

pan eight packets equal 3 OZ., and, therefore, one packet will weigh % oz. The
second illustration shows that in the other pan one packet equals 6 oz. Multi-
ply % by 6 and we get %, the square root of which is 3h, or I ~ oz. as the real
weight of one packet. Therefore, eight packets weigh 12 OZ., which is the cor-
rect answer.


  1. WEIGHING THE BABY


It is important to notice that the man, baby, and dog weigh together 180 lb.,
as recorded on the dial in the illustration. Now, the difference between 180 and
162 is 18, which equals twice the weight of the dog, whose weight is 9 lb.
Therefore the baby weighs 30 lb., since 30 less 70 per cent is 9.


  1. FRESH FRUITS


Since the lower scales tell us that one apple and six plums equal in weight
one pear, we can substitute one apple and six plums for the pear in the upper
scales without disturbing the balance. Then we can remove six plums from
each pan in the upper scales, and find that four apples equal four plums.
Consequently, one apple equals one plum, and if we substitute a plum for the
apple in the lower scales, as they originally stood, we see that seven plums
equal one pear in weight. So the old book says Q.E.D. (quite easily done!).


  1. WEIGHING THE TEA


(1) With the 5 lb. and 9 lb. weights in different pans weigh 4 lb. (2) With
the 4 lb. weigh second 4 lb. (3) Weigh third 4 lb. (4) Weigh fourth 4 lb., and
the remainder will also be 4 lb. (5), (6), (7), (8), (9) Divide each portion
of 4 lb. in turn equally on the two sides of the scales.



  1. AN EXCEPTIONAL NUMBER


1 3452. The successive numbers are 1, 2, 3, 4, 5; 13 X 4 = 52. [Victor
Meally supplies the following solution for a six-digit number: 947,658.
94 X 7 = 658.-M. G.)

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