Java The Complete Reference, Seventh Edition
type information available at run time. Therefore, there is no way forinstanceofto know if iOb2is an instance ofGen2<Integer& ...
Chapter 14: Generics 349 // Demonstrate generic method override. class OverrideDemo { public static void main(String args[]) { / ...
To better understand how erasure works, consider the following two classes: // Here, T is bound by Object by default. class Gen& ...
Chapter 14: Generics 351 Gen iOb = new Gen(99); int x = (Integer) iOb.getob(); Because of erasure, some things work a bit differ ...
352 Part I: The Java Language } // A subclass of Gen. class Gen2 extends Gen<String> { Gen2(String o) { super(o); } // A S ...
Chapter 14: Generics 353 As you can see, the bridge method has been included. (The comment was added by the author, and not byja ...
354 Part I: The Java Language Ambiguity errors can be tricky to fix. For example, if you know thatVwill always be some type ofSt ...
Chapter 14: Generics 355 // Wrong, no static method can use T. static T getob() { return ob; } // Wrong, no static method can ac ...
356 Part I: The Java Language As the program shows, it’s valid to declare a reference to an array of typeT, as this line does: T ...
II The Java Library CHAPTER 15 String Handling CHAPTER 16 Exploring java.lang CHAPTER 17 java.util Part 1: The Collections Frame ...
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15 String Handling A brief overview of Java’s string handling was presented in Chapter 7. In this chapter, it is described in de ...
Frequently, you will want to create strings that have initial values. TheStringclass provides a variety of constructors to handl ...
Chapter 15: String Handling 359 ASCII character set. Because 8-bit ASCII strings are common, theStringclass provides constructor ...
360 Part II: The Java Library The second new constructor supports the newStringBuilderclass. It is shown here: String(StringBuil ...
result. This allows you to chain together a series of+operations. For example, the following fragment concatenates three strings ...
362 Part II: The Java Library that you probably expected. Here’s why. Operator precedence causes the concatenation of “four” wit ...
class toStringDemo { public static void main(String args[]) { Box b = new Box(10, 12, 14); String s = "Box b: " + b; // concaten ...
the characters fromsourceStartthroughsourceEnd–1. The array that will receive the characters is specified bytarget.The index wit ...
equals( ) and equalsIgnoreCase( ) To compare two strings for equality, useequals( ). It has this general form: boolean equals(Ob ...
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