Advanced book on Mathematics Olympiad

(ff) #1

126 3 Real Analysis


Definition.Forx 0 an accumulation point of the domain of a functionf, we say that
limx→x 0 f(x)=Lif for every neighborhoodVofL, there is a neighborhoodUofx 0
such thatf(U)⊂V.


This definition is, however, seldom used in applications. Instead, it is more customary
to use operations with limits, the squeezing principle (iff(x)≤g(x)≤h(x)for allxand
limx→x 0 f(x)=limx→x 0 h(x)=L, then limx→x 0 g(x)=L), continuity, or L’Hôpital’s
theorem, to be discussed later.


Example.Compute


lim
x→∞

(√

x+


x+


x−


x

)

.

Solution.The usual algorithm is to multiply and divide by the conjugate to obtain


lim
x→∞

(√

x+


x+


x−


x

)

=lim
x→∞

x+


x+


x−x

x+


x+


x+


x

=lim
x→∞


x+


x

x+


x+


x+


x

=lim
x→∞


1 +


1
x

1 +


1
x+


1
x^3 +^1

=

1

2

. 

And now an example of type 1∞.

Example.Leta 1 ,a 2 ,...,anbe positive real numbers. Prove that


lim
x→ 0

(

ax 1 +ax 2 +···+axn
n

)^1 x
=n


a 1 a 2 ···an.

Solution.First, note that


lim
x→ 0

ax− 1
x
=lna.

Indeed, the left-hand side can be recognized as the derivative of the exponential at 0. Or
to avoid a logical vicious circle, we can argue as follows: letax= 1 +t, witht→0.
Thenx=ln(ln^1 +at), and the limit becomes


lim
t→ 0

tlna
ln( 1 +t)

=lim
t→ 0

lna
ln( 1 +t)t

=

lna
lne

=lna.
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