Combinatorics and Probability 783
The favorable cases consist of the region
Df=
{
(x, y)∈D|x+y≤ 1 ,xy≤
2
9
}
.
This is the set of points that lie below both the linef(x)= 1 −xand the hyperbola
g(x)= 92 x.
The required probability isP =AreaArea(D(D)f). The area ofDis 1. The area ofDfis
equal to
∫ 1
0
min(f (x), g(x))dx.
The line and the hyperbola intersect at the points(^13 ,^23 )and(^23 ,^13 ). Therefore,
Area(Df)=
∫ 1 / 3
0
( 1 −x)dx+
∫ 2 / 3
1 / 3
2
9 x
dx+
∫ 1
2 / 3
( 1 −x)dx=
1
3
+
2
9
ln 2.
We conclude thatP=^13 +^29 ln 2≈ 0 .487.
(C. Reischer, A. Sâmboan,Culegere de Probleme de Teoria Probabilita ̧ ̆tilor ̧si Statis-
tic ̆a Matematica ̆(Collection of Problems of Probability Theory and Mathematical Statis-
tics), Editura Didactica ̧ ̆si Pedagogica, Bucharest, 1972) ̆
928.The total region is a square of sideβ. The favorable region is the union of the
two triangular regions shown in Figure 109, and hence the probability of a favorable
outcome is
(β−α)^2
β^2
=
(
1 −
α
β
) 2
.
Figure 109
(22nd W.L. Putnam Mathematical Competition, 1961)
929.Denote byx, respectively,y, the fraction of the hour when the husband, respectively,
wife, arrive. The configuration space is the square