Cambridge International AS and A Level Mathematics Pure Mathematics 1

(Michael S) #1
Integration

P1^


6


If  T   is  close   to  P it    is  appropriate to  use the notation    δx  (a  small   change  in  x)
for the difference in their x co-ordinates and δy for the difference in their y
co-ordinates. The area shaded in figure 6.3 is then referred to as δA (a small
change in A).
This area δA will lie between the areas of the rectangles PQRS and UQRT
yδx  δA  (y + δy)δx.
Dividing by δx
y  δ
δ

A

x
 y + δy.
In the limit as δx → 0, δy also approaches zero so δA is sandwiched between y and
something which tends to y.

But                 lim             δ
δ

A

x

A

= x
d
d.
δx → 0

This    gives   ddAx^ = y.

Note
This important result is known as the fundamental theorem of calculus: the rate of
change of the area under a curve is equal to the length of the moving boundary.

EXAMPLE 6.4  Find   the area    under   the curve   y =     6 x^5 + 6   between x = −1  and x = 2.

SOLUTION

Let A   be  the shaded  area    which   is  bounded by  the curve,  the x   axis,   and the 
moving boundary PQ (see figure 6.4).

Then     ddAx^ = y =    6 x^5 + 6.

–1 O 2 x

y

Q

6

P

(xy)

Figure 6.4 

Notice that the
curve crosses
the x axis when
x = –1.
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