Integration
P1^
6
A = B − C
= (^) ∫
3
0 (x^ +^ 1)^ dx^ −^ ∫
3
0 (x
(^2) − 2 x + 1) dx
(^) =+
+
=+()
x^2 x x xx
0
(^33)
2
0
3
23
92 30 27
––
–– 33
9
2
()–– 93 + 0
= squareunits.
Method 2
(^) A x
xx x
=
=+ +
∫{ }
()–( –)
0 topcurve–bottomcurve d
3
((^1221 )
=
=
=
∫
∫
d
d
x
xx x
xx
0
3
2
0
3
23
0
3
3
3
23
(^2729)
(– )
–
–
=
–[]
.
0
9
2 squareunits
EXERCISE 6D 1 The diagram shows the curve
y = x^2 and the line y = 9.
The enclosed region has been shaded.
(i) Find the two points of
intersection (labelled A and B).
(ii) Using integration, show that
the area of the shaded region
is 36 square units.
y
O 1 3 x
y = x^2 – 2x + 1
y = x + 1
Figure 6.20
The height of this rectangle
is the height of the top
curve minus the height of
the bottom curve.
y
O x
A B
y = x2
y = 9