Integration
P1^
6
! Since the integration is ‘with respect to x’, indicated by the dx and the fact that
the limits a and b are values of x, it cannot be evaluated unless the function y is
also written in terms of x.
EXAMPLE 6.18 The region between the curve y = x^2 , the x axis and the lines x = 1 and x = 3 is
rotated through 360° about the x axis.
Find the volume of revolution which is formed.
SOLUTION
The region is shaded in figure 6.29.
Using V = (^) ∫
a
b
πy^2 dx
volume = (^) ∫
1
3
π(x^2 )^2 dx
= (^) ∫
1
3
πx^4 dx
= πx
5
1
3
5
= π 5 (– 243 1 )
= 2425 π.
The volume is 2425 π cubic units or 152 cubic units (3 s.f.).
! Unless a decimal answer is required, it is usual to leave π in the answer, which is
then exact.
O 1 3
y
x
y = x^2
Figure 6.29
Since in this case
y = x^2
y^2 = (x^2 )^2 = x^4.