Co-ordinate geometry
P1^
2
The gradient of the line PQ is
35
24
2
6
1
3
–
–(–)
= =– –
and so the gradient of the perpendicular bisector is +3.
The perpendicular bisector passes throught the mid-point, R, of the line PQ. The
co-ordinates of R are
24
2
35
2
( +(–),(+ )i.e.–,^14 ).
Using y − y 1 = m(x − x 1 ), the equation of the perpendicular bisector is
y − 4 = 3(x − (−1))
y − 4 = 3 x + 3
y = 3 x + 7.
EXERCISE 2C 1 Find the equations of the lines (i) − (x) in the diagrams below.
–4 –2 0 2 4 6 8
–2
–4
2
4
6
x
y
–2 2 4 6 8
–2
2
6
x
y
(iii)
(ii)
(i)
(v)
(iv)
(vii)
(vi)
(x)
(viii)
(ix)
–4
–4 0
4