Co-ordinate geometryP1^
2
The gradient of the line PQ is
35
242
6
1
3
–
–(–)
= =– –
and so the gradient of the perpendicular bisector is +3.
The perpendicular bisector passes throught the mid-point, R, of the line PQ. The
co-ordinates of R are
24
235
2
( +(–),(+ )i.e.–,^14 ).Using y − y 1 = m(x − x 1 ), the equation of the perpendicular bisector is
y − 4 = 3(x − (−1))
y − 4 = 3 x + 3
y = 3 x + 7.EXERCISE 2C 1 Find the equations of the lines (i) − (x) in the diagrams below.–4 –2 0 2 4 6 8
–2–4246xy–2 2 4 6 8
–226xy(iii)
(ii)(i)(v)(iv)(vii)(vi)(x)(viii)(ix)–4–4 04