untitled

Remark : If the digit at the beginning place of recurring point in the number from which

deduction to be made is smaller than that of the digit in the number 1 is to be subtracted

from the extreme right hand digit of the result of subtraction.

Note : In order to make the conception clear why 1 is subtracted, subtraction is done in

another method as shown below :

8 ˜ 24  3  = 8 ˜ 243  43434 | 34

5 ˜ 246  73  = 5 ˜ 246  73673 | 67

2 ˜ 996  69760 | 67

The required difference is 2 ˜ 996  69760 | 67

Here both the differences are the same.

Example 17. Subtract 16 ˜ 4  37  from 24 ˜ 456  45 .

Solution :

24 ˜ 456  45  = 24 ˜ 456  45 

16 ˜ 4  37  = 16 ˜ 437  43 

8 ˜ 01902

 1

[7 is subtracted from 6.1 is to be carried

over.]

8 ˜ 019  01 

The required difference is 8. 019  01 

Note :

24 ˜ 456  45  = 24 ˜ 456  45 | 64

16 ˜ 4  37  = 16 ˜ 437  43 | 74

8 ˜ 019  01 | 90

Activity : Subtract : 1. 10˜418 from 13 ˜ 127  84  2. 9 ˜ 126  45  from 23 ˜ 039  4 

Multiplication and Division of Recurring Decimals :

onverting recurring decimals into simple fraction and completing the process of their C
multiplication or division, the simple fraction thus obtained when expressed into a decimal
fraction will be the product or quotient of the recurring decimals. In the process of
multiplication or division amongst terminating and recurring decimals the same method is to
be applied. But in case of making division easier if both the divident and the divisior are of
recurring decimals, we should convert them into similar recurring decimals.
Example 18. Multiply 4 ˜ 3  by 5 ˜ 7 .