# untitled

(Barré) #1
``````Remark : If the digit at the beginning place of recurring point in the number from which
deduction to be made is smaller than that of the digit in the number 1 is to be subtracted
from the extreme right hand digit of the result of subtraction.
Note : In order to make the conception clear why 1 is subtracted, subtraction is done in
another method as shown below :
8  24  3  = 8  243  43434 | 34
5  246  73  = 5  246  73673 | 67``````

``````2  996  69760 | 67
The required difference is 2  996  69760 | 67
Here both the differences are the same.
Example 17. Subtract 16  4  37  from 24  456  45 .
Solution :
24  456  45  = 24  456  45 
16  4  37  = 16  437  43 
8  01902
 1``````

``````[7 is subtracted from 6.1 is to be carried
over.]
8  019  01 
The required difference is 8. 019  01 
Note :
24  456  45  = 24  456  45 | 64
16  4  37  = 16  437  43 | 74
8  019  01 | 90``````

``````Activity : Subtract : 1. 10418 from 13  127  84  2. 9  126  45  from 23  039  4 
Multiplication and Division of Recurring Decimals :``````

onverting recurring decimals into simple fraction and completing the process of their C
multiplication or division, the simple fraction thus obtained when expressed into a decimal
fraction will be the product or quotient of the recurring decimals. In the process of
multiplication or division amongst terminating and recurring decimals the same method is to
be applied. But in case of making division easier if both the divident and the divisior are of
recurring decimals, we should convert them into similar recurring decimals.
Example 18. Multiply 4  3  by 5  7 .