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(Barré) #1

Now, if we indicate the dividend byf(x), the quotient by h(x), the remainder by r
and the divisor by (xa), from the above formula, we get,


f(x) (xa)˜h(x)r.......... (i) this formula is true to all values of a.

Substituting x a in both sides of (i), we get,
f(a) (aa)˜h(a)r 0 ˜h(a)r r


Hence,r f(a).


Therefore, if f(x) is divided by (xa), the remainder is f(a). This formula is
known as remainder theorem. That is, the remainder theorem gives the remainder
when a polynomial f(x) of positive degree is divided by (xa) without performing
actual division. The degree of the divisor polynomial (xa) is 1. If the divisor is a
factor of the dividend, the remainder will be zero and if it is not zero, the remainder
will be a number other than zero.
Proposition : If the degree of f(x) is positive and az 0 , f(x) is divided by


(axb), remainder is ̧
¹

·
̈
©

§
a

b
f.

Proof : Degree of the divisor axb,(az 0 ) is 1.
Hence, we can write,


hx r
a

b
fx ax b hx r ax ̧˜ 
¹

·
̈
©

() (  )˜() §  ()

? ahx r
a


f x x b ˜ ˜ 
̧
¹

·
̈
©

() §  ()

Observe that, if f(x) is divided by ̧
¹


·
̈
©

§ 
a
x b, quotient is a˜h(x) and remainder is r.

Here, divisor = ̧
¹


·
̈
©

§
a
x b

Hence, according to remainder theorem, ̧
¹


̈ ·
©

§
a

b
r f

Therefore, if f(x) is divided by (axb), remainder is ̧
¹


·
̈
©

§

a

b
f.

Corollary :(xa) will be a factor of f(x), if and only if f(a) 0.


Proof : Let, f(a) 0


Therefore, according to remainder theorem, if f(x) is divided by (xa), the
remainder will be zero. That is, (xa) will be a factor of f(x).


Conversely, let, (xa) is a factor of f(x).


Therefore, f(x) (xa)˜h(x), where h(x) is a polynomial.


Putting x a in both sides, we get,

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