0DWK,;;)RUPD
= anum amn
? (am)n amn
Example 1. Find the values (a) 3
2
5
5
(b)
5 5
3
2
3
2
̧
¹
·
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§
̧u
¹
·
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§
Solution :(a) 3
2
5
5
=
5
1
5
1
52 ^3 5 ^1 1
(b)
5 5
3
2
3
2
̧
¹
·
̈
©
§
̧u
¹
·
̈
©
§
= 1
3
2
3
2
55 0
̧^
¹
·
̈
©
§
̧^
¹
·
̈
©
§
Example 2. Simplify : (a)
2 125
5 8 16
5
4
u
u u
(b)
1
2
2 2
3 2 4 2
n n
n n
Solution: (a)^4375
5
7
3
4
3 5
4 3 4
5 3
4 3 4
5
4
5 2
2
2
5
5
5 2
5 2
2 5
5 2 2
2 125
5 8 16
u u
u
u
u
u u
u
u u
20 51 u 22 5 u 4
(b)
2
1
2 2
32 2
2 2 2
32 2 2
2 2
32 42 2 2
1
2 2
1
2
n n
n n
n n
n n
n n
n n
22 4.
2
2
1
2 2
2
2
1
( 3 1 ) 2
2
1
1
32 2
2
̧
¹
·
̈
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§
n
n
n
n
n
n n
Example 3. Show that (ap)qr(aq)rp(ar)pq 1
Solution : (ap)qr(aq)rp(ar)pq
1.
[ )
0
( ) ( ) ( )
a
a
a a a
a a a (a a
pqprqrpqprqr
pqpr qrpq prqr
pqr qrp rpq mn ]mn
Activity : Fill in the blank boxes :
(i) 3 u 3 u 3 u 3 3 (ii) 5 u 53 55 (iii)a^2 ua a^3 (iv) 1
4
4
(v)( 5 )^0