PRELIMINARY CALCULUS
∆x∆s ∆yy=f(x)xf(x)Figure 2.11 The distance moved along a curve, ∆s, corresponding to the
small changes ∆xand ∆y.In plane polar coordinates,ds=√
(dr)^2 +(rdφ)^2 ⇒ s=∫r 2r 1√1+r^2(
dφ
dr) 2
dr.
(2.43)Find the length of the curvey=x^3 /^2 fromx=0tox=2.Using (2.42) and noting thatdy/dx=^32
√
x, the lengthsof the curve is given bys=∫ 2
0√
1+^94 xdx=
[
2
3( 4
9)(
1+^94 x) 3 / 2 ] 2
0= 278
[(
1+^94 x) 3 / 2 ] 2
0
= 278[(
11
2) 3 / 2
− 1
]
.
Surfaces of revolutionConsider the surfaceSformed by rotating the curvey=f(x) about thex-axis
(see figure 2.12). The surface area of the ‘collar’ formed by rotating an element
of the curve,ds, about thex-axis is 2πy ds, and hence the total surface area is
S=∫ba2 πy ds.Since (ds)^2 =(dx)^2 +(dy)^2 from (2.41), the total surface area between the planes
x=aandx=bis
S=∫ba2 πy√1+(
dy
dx) 2
dx. (2.44)