PRELIMINARY CALCULUS
∆x
∆s ∆y
y=f(x)
x
f(x)
Figure 2.11 The distance moved along a curve, ∆s, corresponding to the
small changes ∆xand ∆y.
In plane polar coordinates,
ds=
√
(dr)^2 +(rdφ)^2 ⇒ s=
∫r 2
r 1
√
1+r^2
(
dφ
dr
) 2
dr.
(2.43)
Find the length of the curvey=x^3 /^2 fromx=0tox=2.
Using (2.42) and noting thatdy/dx=^32
√
x, the lengthsof the curve is given by
s=
∫ 2
0
√
1+^94 xdx
=
[
2
3
( 4
9
)(
1+^94 x
) 3 / 2 ] 2
0
= 278
[(
1+^94 x
) 3 / 2 ] 2
0
= 278
[(
11
2
) 3 / 2
− 1
]
.
Surfaces of revolution
Consider the surfaceSformed by rotating the curvey=f(x) about thex-axis
(see figure 2.12). The surface area of the ‘collar’ formed by rotating an element
of the curve,ds, about thex-axis is 2πy ds, and hence the total surface area is
S=
∫b
a
2 πy ds.
Since (ds)^2 =(dx)^2 +(dy)^2 from (2.41), the total surface area between the planes
x=aandx=bis
S=
∫b
a
2 πy
√
1+
(
dy
dx
) 2
dx. (2.44)