PROBABILITY
A random variableXhas a PDFf(x)given byAe−xin the interval 0 <x<∞and zero
elsewhere. Find the value of the constantAand hence calculate the probability thatXlies
in the interval 1 <X≤ 2.
We require the integral off(x) between 0 and∞to equal unity. Evaluating this integral,
we find ∫
∞
0
Ae−xdx=
[
−Ae−x
]∞
0 =A,
and henceA= 1. From (30.42), we then obtain
Pr(1<X≤2) =
∫ 2
1
f(x)dx=
∫ 2
1
e−xdx=−e−^2 −(−e−^1 )=0. 23 .
It is worth mentioning here that adiscreteRV can in fact be treated as
continuous and assigned a corresponding probability density function. IfXis a
discrete RV that takes only the valuesx 1 ,x 2 ,...,xnwith probabilitiesp 1 ,p 2 ,...,pn
then we may describeXas a continuous RV with PDF
f(x)=
∑n
i=1
piδ(x−xi), (30.44)
whereδ(x) is the Dirac delta function discussed in subsection 13.1.3. From (30.42)
and the fundamental property of the delta function (13.12), we see that
Pr(a<X≤b)=
∫b
a
f(x)dx,
=
∑n
i=1
pi
∫b
a
δ(x−xi)dx=
∑
i
pi,
where the final sum extends over those values ofifor whicha<xi≤b.
30.4.3 Sets of random variables
It is common in practice to consider two or more random variables simultane-
ously. For example, one might be interested in both the height and weight of
a person drawn at random from a population. In the general case, these vari-
ables may depend on one another and are described byjoint probability density
functions; these are discussed fully in section 30.11. We simply note here that if
we have (say) two random variablesXandYthen by analogy with the single-
variable case we define their joint probability density functionf(x, y)insucha
way that, ifXandYare discrete RVs,
Pr(X=xi,Y=yj)=f(xi,yj),
or, ifXandYare continuous RVs,
Pr(x<X≤x+dx, y < Y≤y+dy)=f(x, y)dx dy.