PROBABILITY
the series is absolutely convergent or that the integral exists, as the case may be.
From its definition it is straightforward to show that the expectation value has
the following properties:
(i) ifais a constant thenE[a]=a;
(ii) ifais a constant thenE[ag(X)] =aE[g(X)];
(iii) ifg(X)=s(X)+t(X)thenE[g(X)] =E[s(X)] +E[t(X)].
It should be noted that the expectation value is not a function ofXbut is
instead a number that depends on the form of the probability density function
f(x) and the functiong(x). Most of the standard quantities used to characterise
f(x) are simply the expectation values of various functions of the random variable
X. We now consider these standard quantities.
30.5.1 Mean
The property most commonly used to characterise a probability distribution is
itsmean, which is defined simply as the expectation valueE[X] of the variableX
itself. Thus, the mean is given by
E[X]=
{∑
∫ixif(xi) for a discrete distribution,
xf(x)dx for a continuous distribution.
(30.46)
The alternative notationsμand〈x〉are also commonly used to denote the mean.
If in (30.46) the series is not absolutely convergent, or the integral does not exist,
we say that the distribution does not have a mean, but this is very rare in physical
applications.
The probability of finding a1selectron in a hydrogen atom in a given infinitesimal volume
dVisψ∗ψdV, where the quantum mechanical wavefunctionψis given by
ψ=Ae−r/a^0.
Find the value of the real constantAand thereby deduce the mean distance of the electron
from the origin.
Let us consider the random variableR= ‘distance of the electron from the origin’. Since
the 1s orbital has noθ-orφ-dependence (it is spherically symmetric), we may consider
the infinitesimal volume elementdVas the spherical shell with inner radiusrand outer
radiusr+dr. Thus,dV=4πr^2 drand the PDF ofRis simply
Pr(r<R≤r+dr)≡f(r)dr=4πr^2 A^2 e−^2 r/a^0 dr.
The value ofAis found by requiring the total probability (i.e. the probability that the
electron issomewhere) to be unity. SinceRmust lie between zero and infinity, we require
that
A^2
∫∞
0
e−^2 r/a^04 πr^2 dr=1.