COMPLEX NUMBERS AND HYPERBOLIC FUNCTIONS
Rez
Imz
e−^2 iπ/^3
e^2 iπ/^3
2 π/ 3
2 π/ 3
1
Figure 3.10 The solutions ofz^3 =1.
Not surprisingly, given that|z^3 |=|z|^3 from (3.10), all the roots of unity have
unit modulus, i.e. they all lie on a circle in the Argand diagram of unit radius.
The three roots are shown in figure 3.10.
The cube roots of unity are often written 1,ωandω^2. The propertiesω^3 =1
and 1 +ω+ω^2 = 0 are easily proved.
3.4.3 Solving polynomial equations
A third application of de Moivre’s theorem is to the solution of polynomial
equations. Complex equations in the form of a polynomial relationship must first
be solved forzin a similar fashion to the method for finding the roots of real
polynomial equations. Then the complex roots ofzmay be found.
Solve the equationz^6 −z^5 +4z^4 − 6 z^3 +2z^2 − 8 z+8=0.
We first factorise to give
(z^3 −2)(z^2 +4)(z−1) = 0.
Hencez^3 =2orz^2 =−4orz= 1. The solutions to the quadratic equation arez=± 2 i;
to find the complex cube roots, we first write the equation in the form
z^3 =2=2e^2 ikπ,
wherekis any integer. If we now take the cube root, we get
z=2^1 /^3 e^2 ikπ/^3.