PARTIAL DIFFERENTIATION
it exact. Consider the general differential containing two variables,
df=A(x, y)dx+B(x, y)dy.
We see that
∂f
∂x
=A(x, y),
∂f
∂y
=B(x, y)
and, using the propertyfxy=fyx, we therefore require
∂A
∂y
=
∂B
∂x
. (5.9)
This is in fact both a necessary and a sufficient condition for the differential to
be exact.
Using (5.9) show thatxdy+3ydxis inexact.
In the above notation,A(x, y)=3yandB(x, y)=xand so
∂A
∂y
=3,
∂B
∂x
=1.
As these are not equal it follows that the differential is inexact.
Determining whether a differential containing many variablex 1 ,x 2 ,...,xnis
exact is a simple extension of the above. A differential containing many variables
canbewritteningeneralas
df=
∑n
i=1
gi(x 1 ,x 2 ,...,xn)dxi
and will be exact if
∂gi
∂xj
=
∂gj
∂xi
for all pairsi, j. (5.10)
There will be^12 n(n−1) such relationships to be satisfied.
Show that
(y+z)dx+xdy+xdz
is an exact differential.
In this case,g 1 (x, y, z)=y+z,g 2 (x, y, z)=x,g 3 (x, y, z)=xand hence∂g 1 /∂y=1=
∂g 2 /∂x,∂g 3 /∂x=1=∂g 1 /∂z,∂g 2 /∂z=0=∂g 3 /∂y; therefore, from (5.10), the differential
is exact. As mentioned above, it is sometimes possible to show that a differential is exact
simply by finding by inspection the function from which it originates. In this example, it
can be seen easily thatf(x, y, z)=x(y+z)+c.