5.13 EXERCISES
constant limits of integration the order of integration and differentiation can be
reversed.
In the more general case where the limits of the integral are themselves functions
ofx, it follows immediately that
I(x)=
∫t=v(x)
t=u(x)
f(x, t)dt
=F(x, v(x))−F(x, u(x)),
which yields the partial derivatives
∂I
∂v
=f(x, v(x)),
∂I
∂u
=−f(x, u(x)).
Consequently
dI
dx
=
(
∂I
∂v
)
dv
dx
+
(
∂I
∂u
)
du
dx
+
∂I
∂x
=f(x, v(x))
dv
dx
−f(x, u(x))
du
dx
+
∂
∂x
∫v(x)
u(x)
f(x, t)dt
=f(x, v(x))
dv
dx
−f(x, u(x))
du
dx
+
∫v(x)
u(x)
∂f(x, t)
∂x
dt, (5.47)
where the partial derivative with respect toxin the last term has been taken
inside the integral sign using (5.46). This procedure is valid becauseu(x)andv(x)
are being held constant in this term.
Find the derivative with respect toxof the integral
I(x)=
∫x 2
x
sinxt
t
dt.
Applying (5.47), we see that
dI
dx
=
sinx^3
x^2
(2x)−
sinx^2
x
(1) +
∫x 2
x
tcosxt
t
dt
=
2sinx^3
x
−
sinx^2
x
+
[
sinxt
x
]x 2
x
=3
sinx^3
x
− 2
sinx^2
x
=
1
x
(3 sinx^3 −2sinx^2 ).
5.13 Exercises
5.1 Using the appropriate properties of ordinary derivatives, perform the following.