VECTOR ALGEBRA
O
A
P
θp−a dabpFigure 7.14 The minimum distance from a point to a line.Find the minimum distance from the pointPwith coordinates(1, 2 ,1)to the liner=a+λb,
wherea=i+j+kandb=2i−j+3k.Comparison with (7.39) shows that the line passes through the point (1, 1 ,1) and has
direction 2i−j+3k. The unit vector in this direction is
ˆb=√^1
14(2i−j+3k).The position vector ofPisp=i+2j+kand we find
(p−a)×bˆ=1
√
14
[j×(2i− 3 j+3k)]=
1
√
14
(3i− 2 k).Thus the minimum distance from the line to the pointPisd=
√
13 /14.
7.8.2 Distance from a point to a planeThe minimum distancedfrom a pointPwhose position vector ispto the plane
defined by (r−a)·nˆ= 0 may be deduced by finding any vector fromPto the
plane and then determining its component in the normal direction. This is shown
in figure 7.15. Consider the vectora−p, which is a particular vector fromPto
the plane. Its component normal to the plane, and hence its distance from the
plane, is given by
d=(a−p)·nˆ, (7.46)where the sign ofddepends on which side of the planePis situated.