VECTOR CALCULUS
ρ, φ, z,where
x=ρcosφ, y=ρsinφ, z=z, (10.44)
andρ≥0, 0≤φ< 2 πand−∞<z<∞. The position vector ofPmay therefore
be written
r=ρcosφi+ρsinφj+zk. (10.45)
If we take the partial derivatives ofrwith respect toρ,φandzrespectively then
we obtain the three vectors
eρ=
∂r
∂ρ
=cosφi+sinφj, (10.46)
eφ=
∂r
∂φ
=−ρsinφi+ρcosφj, (10.47)
ez=
∂r
∂z
=k. (10.48)
These vectors lie in the directions of increasingρ,φandzrespectively but are
not all of unit length. Althougheρ,eφandezform a useful set of basis vectors
in their own right (we will see in section 10.10 that such a basis is sometimes the
mostuseful), it is usual to work with the correspondingunitvectors, which are
obtained by dividing each vector by its modulus to give
eˆρ=eρ=cosφi+sinφj, (10.49)
ˆeφ=
1
ρ
eφ=−sinφi+cosφj, (10.50)
ˆez=ez=k. (10.51)
These three unit vectors, like the Cartesian unit vectorsi,jandk,forman
orthonormal triad at each point in space, i.e. the basis vectors are mutually
orthogonal and of unit length (see figure 10.7). Unlike the fixed vectorsi,jandk,
however,ˆeρandeˆφchange direction asPmoves.
The expression for a general infinitesimal vector displacementdrin the position
ofPis given, from (10.19), by
dr=
∂r
∂ρ
dρ+
∂r
∂φ
dφ+
∂r
∂z
dz
=dρeρ+dφeφ+dzez
=dρeˆρ+ρdφeˆφ+dzeˆz. (10.52)
This expression illustrates an important difference between Cartesian and cylin-
drical polar coordinates (or non-Cartesian coordinates in general). In Cartesian
coordinates, the distance moved in going fromxtox+dx, withyandzheld
constant, is simplyds=dx. However, in cylindrical polars, ifφchanges bydφ,
withρandzheld constant, then the distance moved isnotdφ, butds=ρdφ.